3.10.6 \(\int \frac {(a+b x)^3 (A+B x)}{(d+e x)^5} \, dx\)

Optimal. Leaf size=129 \[ -\frac {(a+b x)^4 (B d-A e)}{4 e (d+e x)^4 (b d-a e)}+\frac {3 b^2 B (b d-a e)}{e^5 (d+e x)}-\frac {3 b B (b d-a e)^2}{2 e^5 (d+e x)^2}+\frac {B (b d-a e)^3}{3 e^5 (d+e x)^3}+\frac {b^3 B \log (d+e x)}{e^5} \]

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Rubi [A]  time = 0.11, antiderivative size = 129, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {78, 43} \begin {gather*} -\frac {(a+b x)^4 (B d-A e)}{4 e (d+e x)^4 (b d-a e)}+\frac {3 b^2 B (b d-a e)}{e^5 (d+e x)}-\frac {3 b B (b d-a e)^2}{2 e^5 (d+e x)^2}+\frac {B (b d-a e)^3}{3 e^5 (d+e x)^3}+\frac {b^3 B \log (d+e x)}{e^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((a + b*x)^3*(A + B*x))/(d + e*x)^5,x]

[Out]

-((B*d - A*e)*(a + b*x)^4)/(4*e*(b*d - a*e)*(d + e*x)^4) + (B*(b*d - a*e)^3)/(3*e^5*(d + e*x)^3) - (3*b*B*(b*d
- a*e)^2)/(2*e^5*(d + e*x)^2) + (3*b^2*B*(b*d - a*e))/(e^5*(d + e*x)) + (b^3*B*Log[d + e*x])/e^5

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rubi steps

\begin {align*} \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^5} \, dx &=-\frac {(B d-A e) (a+b x)^4}{4 e (b d-a e) (d+e x)^4}+\frac {B \int \frac {(a+b x)^3}{(d+e x)^4} \, dx}{e}\\ &=-\frac {(B d-A e) (a+b x)^4}{4 e (b d-a e) (d+e x)^4}+\frac {B \int \left (\frac {(-b d+a e)^3}{e^3 (d+e x)^4}+\frac {3 b (b d-a e)^2}{e^3 (d+e x)^3}-\frac {3 b^2 (b d-a e)}{e^3 (d+e x)^2}+\frac {b^3}{e^3 (d+e x)}\right ) \, dx}{e}\\ &=-\frac {(B d-A e) (a+b x)^4}{4 e (b d-a e) (d+e x)^4}+\frac {B (b d-a e)^3}{3 e^5 (d+e x)^3}-\frac {3 b B (b d-a e)^2}{2 e^5 (d+e x)^2}+\frac {3 b^2 B (b d-a e)}{e^5 (d+e x)}+\frac {b^3 B \log (d+e x)}{e^5}\\ \end {align*}

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Mathematica [A]  time = 0.11, size = 222, normalized size = 1.72 \begin {gather*} \frac {-a^3 e^3 (3 A e+B (d+4 e x))-3 a^2 b e^2 \left (A e (d+4 e x)+B \left (d^2+4 d e x+6 e^2 x^2\right )\right )-3 a b^2 e \left (A e \left (d^2+4 d e x+6 e^2 x^2\right )+3 B \left (d^3+4 d^2 e x+6 d e^2 x^2+4 e^3 x^3\right )\right )+b^3 \left (B d \left (25 d^3+88 d^2 e x+108 d e^2 x^2+48 e^3 x^3\right )-3 A e \left (d^3+4 d^2 e x+6 d e^2 x^2+4 e^3 x^3\right )\right )+12 b^3 B (d+e x)^4 \log (d+e x)}{12 e^5 (d+e x)^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x)^3*(A + B*x))/(d + e*x)^5,x]

[Out]

(-(a^3*e^3*(3*A*e + B*(d + 4*e*x))) - 3*a^2*b*e^2*(A*e*(d + 4*e*x) + B*(d^2 + 4*d*e*x + 6*e^2*x^2)) - 3*a*b^2*
e*(A*e*(d^2 + 4*d*e*x + 6*e^2*x^2) + 3*B*(d^3 + 4*d^2*e*x + 6*d*e^2*x^2 + 4*e^3*x^3)) + b^3*(-3*A*e*(d^3 + 4*d
^2*e*x + 6*d*e^2*x^2 + 4*e^3*x^3) + B*d*(25*d^3 + 88*d^2*e*x + 108*d*e^2*x^2 + 48*e^3*x^3)) + 12*b^3*B*(d + e*
x)^4*Log[d + e*x])/(12*e^5*(d + e*x)^4)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^5} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[((a + b*x)^3*(A + B*x))/(d + e*x)^5,x]

[Out]

IntegrateAlgebraic[((a + b*x)^3*(A + B*x))/(d + e*x)^5, x]

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fricas [B]  time = 0.87, size = 354, normalized size = 2.74 \begin {gather*} \frac {25 \, B b^{3} d^{4} - 3 \, A a^{3} e^{4} - 3 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} e - 3 \, {\left (B a^{2} b + A a b^{2}\right )} d^{2} e^{2} - {\left (B a^{3} + 3 \, A a^{2} b\right )} d e^{3} + 12 \, {\left (4 \, B b^{3} d e^{3} - {\left (3 \, B a b^{2} + A b^{3}\right )} e^{4}\right )} x^{3} + 18 \, {\left (6 \, B b^{3} d^{2} e^{2} - {\left (3 \, B a b^{2} + A b^{3}\right )} d e^{3} - {\left (B a^{2} b + A a b^{2}\right )} e^{4}\right )} x^{2} + 4 \, {\left (22 \, B b^{3} d^{3} e - 3 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e^{2} - 3 \, {\left (B a^{2} b + A a b^{2}\right )} d e^{3} - {\left (B a^{3} + 3 \, A a^{2} b\right )} e^{4}\right )} x + 12 \, {\left (B b^{3} e^{4} x^{4} + 4 \, B b^{3} d e^{3} x^{3} + 6 \, B b^{3} d^{2} e^{2} x^{2} + 4 \, B b^{3} d^{3} e x + B b^{3} d^{4}\right )} \log \left (e x + d\right )}{12 \, {\left (e^{9} x^{4} + 4 \, d e^{8} x^{3} + 6 \, d^{2} e^{7} x^{2} + 4 \, d^{3} e^{6} x + d^{4} e^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^3*(B*x+A)/(e*x+d)^5,x, algorithm="fricas")

[Out]

1/12*(25*B*b^3*d^4 - 3*A*a^3*e^4 - 3*(3*B*a*b^2 + A*b^3)*d^3*e - 3*(B*a^2*b + A*a*b^2)*d^2*e^2 - (B*a^3 + 3*A*
a^2*b)*d*e^3 + 12*(4*B*b^3*d*e^3 - (3*B*a*b^2 + A*b^3)*e^4)*x^3 + 18*(6*B*b^3*d^2*e^2 - (3*B*a*b^2 + A*b^3)*d*
e^3 - (B*a^2*b + A*a*b^2)*e^4)*x^2 + 4*(22*B*b^3*d^3*e - 3*(3*B*a*b^2 + A*b^3)*d^2*e^2 - 3*(B*a^2*b + A*a*b^2)
*d*e^3 - (B*a^3 + 3*A*a^2*b)*e^4)*x + 12*(B*b^3*e^4*x^4 + 4*B*b^3*d*e^3*x^3 + 6*B*b^3*d^2*e^2*x^2 + 4*B*b^3*d^
3*e*x + B*b^3*d^4)*log(e*x + d))/(e^9*x^4 + 4*d*e^8*x^3 + 6*d^2*e^7*x^2 + 4*d^3*e^6*x + d^4*e^5)

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giac [B]  time = 1.29, size = 447, normalized size = 3.47 \begin {gather*} -B b^{3} e^{\left (-5\right )} \log \left (\frac {{\left | x e + d \right |} e^{\left (-1\right )}}{{\left (x e + d\right )}^{2}}\right ) + \frac {1}{12} \, {\left (\frac {48 \, B b^{3} d e^{15}}{x e + d} - \frac {36 \, B b^{3} d^{2} e^{15}}{{\left (x e + d\right )}^{2}} + \frac {16 \, B b^{3} d^{3} e^{15}}{{\left (x e + d\right )}^{3}} - \frac {3 \, B b^{3} d^{4} e^{15}}{{\left (x e + d\right )}^{4}} - \frac {36 \, B a b^{2} e^{16}}{x e + d} - \frac {12 \, A b^{3} e^{16}}{x e + d} + \frac {54 \, B a b^{2} d e^{16}}{{\left (x e + d\right )}^{2}} + \frac {18 \, A b^{3} d e^{16}}{{\left (x e + d\right )}^{2}} - \frac {36 \, B a b^{2} d^{2} e^{16}}{{\left (x e + d\right )}^{3}} - \frac {12 \, A b^{3} d^{2} e^{16}}{{\left (x e + d\right )}^{3}} + \frac {9 \, B a b^{2} d^{3} e^{16}}{{\left (x e + d\right )}^{4}} + \frac {3 \, A b^{3} d^{3} e^{16}}{{\left (x e + d\right )}^{4}} - \frac {18 \, B a^{2} b e^{17}}{{\left (x e + d\right )}^{2}} - \frac {18 \, A a b^{2} e^{17}}{{\left (x e + d\right )}^{2}} + \frac {24 \, B a^{2} b d e^{17}}{{\left (x e + d\right )}^{3}} + \frac {24 \, A a b^{2} d e^{17}}{{\left (x e + d\right )}^{3}} - \frac {9 \, B a^{2} b d^{2} e^{17}}{{\left (x e + d\right )}^{4}} - \frac {9 \, A a b^{2} d^{2} e^{17}}{{\left (x e + d\right )}^{4}} - \frac {4 \, B a^{3} e^{18}}{{\left (x e + d\right )}^{3}} - \frac {12 \, A a^{2} b e^{18}}{{\left (x e + d\right )}^{3}} + \frac {3 \, B a^{3} d e^{18}}{{\left (x e + d\right )}^{4}} + \frac {9 \, A a^{2} b d e^{18}}{{\left (x e + d\right )}^{4}} - \frac {3 \, A a^{3} e^{19}}{{\left (x e + d\right )}^{4}}\right )} e^{\left (-20\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^3*(B*x+A)/(e*x+d)^5,x, algorithm="giac")

[Out]

-B*b^3*e^(-5)*log(abs(x*e + d)*e^(-1)/(x*e + d)^2) + 1/12*(48*B*b^3*d*e^15/(x*e + d) - 36*B*b^3*d^2*e^15/(x*e
+ d)^2 + 16*B*b^3*d^3*e^15/(x*e + d)^3 - 3*B*b^3*d^4*e^15/(x*e + d)^4 - 36*B*a*b^2*e^16/(x*e + d) - 12*A*b^3*e
^16/(x*e + d) + 54*B*a*b^2*d*e^16/(x*e + d)^2 + 18*A*b^3*d*e^16/(x*e + d)^2 - 36*B*a*b^2*d^2*e^16/(x*e + d)^3
- 12*A*b^3*d^2*e^16/(x*e + d)^3 + 9*B*a*b^2*d^3*e^16/(x*e + d)^4 + 3*A*b^3*d^3*e^16/(x*e + d)^4 - 18*B*a^2*b*e
^17/(x*e + d)^2 - 18*A*a*b^2*e^17/(x*e + d)^2 + 24*B*a^2*b*d*e^17/(x*e + d)^3 + 24*A*a*b^2*d*e^17/(x*e + d)^3
- 9*B*a^2*b*d^2*e^17/(x*e + d)^4 - 9*A*a*b^2*d^2*e^17/(x*e + d)^4 - 4*B*a^3*e^18/(x*e + d)^3 - 12*A*a^2*b*e^18
/(x*e + d)^3 + 3*B*a^3*d*e^18/(x*e + d)^4 + 9*A*a^2*b*d*e^18/(x*e + d)^4 - 3*A*a^3*e^19/(x*e + d)^4)*e^(-20)

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maple [B]  time = 0.01, size = 430, normalized size = 3.33 \begin {gather*} -\frac {A \,a^{3}}{4 \left (e x +d \right )^{4} e}+\frac {3 A \,a^{2} b d}{4 \left (e x +d \right )^{4} e^{2}}-\frac {3 A a \,b^{2} d^{2}}{4 \left (e x +d \right )^{4} e^{3}}+\frac {A \,b^{3} d^{3}}{4 \left (e x +d \right )^{4} e^{4}}+\frac {B \,a^{3} d}{4 \left (e x +d \right )^{4} e^{2}}-\frac {3 B \,a^{2} b \,d^{2}}{4 \left (e x +d \right )^{4} e^{3}}+\frac {3 B a \,b^{2} d^{3}}{4 \left (e x +d \right )^{4} e^{4}}-\frac {B \,b^{3} d^{4}}{4 \left (e x +d \right )^{4} e^{5}}-\frac {A \,a^{2} b}{\left (e x +d \right )^{3} e^{2}}+\frac {2 A a \,b^{2} d}{\left (e x +d \right )^{3} e^{3}}-\frac {A \,b^{3} d^{2}}{\left (e x +d \right )^{3} e^{4}}-\frac {B \,a^{3}}{3 \left (e x +d \right )^{3} e^{2}}+\frac {2 B \,a^{2} b d}{\left (e x +d \right )^{3} e^{3}}-\frac {3 B a \,b^{2} d^{2}}{\left (e x +d \right )^{3} e^{4}}+\frac {4 B \,b^{3} d^{3}}{3 \left (e x +d \right )^{3} e^{5}}-\frac {3 A a \,b^{2}}{2 \left (e x +d \right )^{2} e^{3}}+\frac {3 A \,b^{3} d}{2 \left (e x +d \right )^{2} e^{4}}-\frac {3 B \,a^{2} b}{2 \left (e x +d \right )^{2} e^{3}}+\frac {9 B a \,b^{2} d}{2 \left (e x +d \right )^{2} e^{4}}-\frac {3 B \,b^{3} d^{2}}{\left (e x +d \right )^{2} e^{5}}-\frac {A \,b^{3}}{\left (e x +d \right ) e^{4}}-\frac {3 B a \,b^{2}}{\left (e x +d \right ) e^{4}}+\frac {4 B \,b^{3} d}{\left (e x +d \right ) e^{5}}+\frac {B \,b^{3} \ln \left (e x +d \right )}{e^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^3*(B*x+A)/(e*x+d)^5,x)

[Out]

-b^3/e^4/(e*x+d)*A-3*b^2/e^4/(e*x+d)*B*a+4*b^3/e^5/(e*x+d)*B*d-1/e^2/(e*x+d)^3*A*a^2*b+2/e^3/(e*x+d)^3*A*d*a*b
^2-1/e^4/(e*x+d)^3*A*d^2*b^3-1/3/e^2/(e*x+d)^3*B*a^3+2/e^3/(e*x+d)^3*B*d*a^2*b-3/e^4/(e*x+d)^3*B*d^2*a*b^2+4/3
/e^5/(e*x+d)^3*B*b^3*d^3-1/4/e/(e*x+d)^4*A*a^3+3/4/e^2/(e*x+d)^4*A*d*a^2*b-3/4/e^3/(e*x+d)^4*A*d^2*a*b^2+1/4/e
^4/(e*x+d)^4*A*d^3*b^3+1/4/e^2/(e*x+d)^4*B*d*a^3-3/4/e^3/(e*x+d)^4*B*d^2*a^2*b+3/4/e^4/(e*x+d)^4*B*d^3*a*b^2-1
/4/e^5/(e*x+d)^4*B*b^3*d^4+b^3*B*ln(e*x+d)/e^5-3/2*b^2/e^3/(e*x+d)^2*A*a+3/2*b^3/e^4/(e*x+d)^2*A*d-3/2*b/e^3/(
e*x+d)^2*B*a^2+9/2*b^2/e^4/(e*x+d)^2*B*d*a-3*b^3/e^5/(e*x+d)^2*B*d^2

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maxima [B]  time = 0.52, size = 302, normalized size = 2.34 \begin {gather*} \frac {25 \, B b^{3} d^{4} - 3 \, A a^{3} e^{4} - 3 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} e - 3 \, {\left (B a^{2} b + A a b^{2}\right )} d^{2} e^{2} - {\left (B a^{3} + 3 \, A a^{2} b\right )} d e^{3} + 12 \, {\left (4 \, B b^{3} d e^{3} - {\left (3 \, B a b^{2} + A b^{3}\right )} e^{4}\right )} x^{3} + 18 \, {\left (6 \, B b^{3} d^{2} e^{2} - {\left (3 \, B a b^{2} + A b^{3}\right )} d e^{3} - {\left (B a^{2} b + A a b^{2}\right )} e^{4}\right )} x^{2} + 4 \, {\left (22 \, B b^{3} d^{3} e - 3 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e^{2} - 3 \, {\left (B a^{2} b + A a b^{2}\right )} d e^{3} - {\left (B a^{3} + 3 \, A a^{2} b\right )} e^{4}\right )} x}{12 \, {\left (e^{9} x^{4} + 4 \, d e^{8} x^{3} + 6 \, d^{2} e^{7} x^{2} + 4 \, d^{3} e^{6} x + d^{4} e^{5}\right )}} + \frac {B b^{3} \log \left (e x + d\right )}{e^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^3*(B*x+A)/(e*x+d)^5,x, algorithm="maxima")

[Out]

1/12*(25*B*b^3*d^4 - 3*A*a^3*e^4 - 3*(3*B*a*b^2 + A*b^3)*d^3*e - 3*(B*a^2*b + A*a*b^2)*d^2*e^2 - (B*a^3 + 3*A*
a^2*b)*d*e^3 + 12*(4*B*b^3*d*e^3 - (3*B*a*b^2 + A*b^3)*e^4)*x^3 + 18*(6*B*b^3*d^2*e^2 - (3*B*a*b^2 + A*b^3)*d*
e^3 - (B*a^2*b + A*a*b^2)*e^4)*x^2 + 4*(22*B*b^3*d^3*e - 3*(3*B*a*b^2 + A*b^3)*d^2*e^2 - 3*(B*a^2*b + A*a*b^2)
*d*e^3 - (B*a^3 + 3*A*a^2*b)*e^4)*x)/(e^9*x^4 + 4*d*e^8*x^3 + 6*d^2*e^7*x^2 + 4*d^3*e^6*x + d^4*e^5) + B*b^3*l
og(e*x + d)/e^5

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mupad [B]  time = 0.16, size = 303, normalized size = 2.35 \begin {gather*} \frac {B\,b^3\,\ln \left (d+e\,x\right )}{e^5}-\frac {\frac {B\,a^3\,d\,e^3+3\,A\,a^3\,e^4+3\,B\,a^2\,b\,d^2\,e^2+3\,A\,a^2\,b\,d\,e^3+9\,B\,a\,b^2\,d^3\,e+3\,A\,a\,b^2\,d^2\,e^2-25\,B\,b^3\,d^4+3\,A\,b^3\,d^3\,e}{12\,e^5}+\frac {x\,\left (B\,a^3\,e^3+3\,B\,a^2\,b\,d\,e^2+3\,A\,a^2\,b\,e^3+9\,B\,a\,b^2\,d^2\,e+3\,A\,a\,b^2\,d\,e^2-22\,B\,b^3\,d^3+3\,A\,b^3\,d^2\,e\right )}{3\,e^4}+\frac {3\,x^2\,\left (B\,a^2\,b\,e^2+3\,B\,a\,b^2\,d\,e+A\,a\,b^2\,e^2-6\,B\,b^3\,d^2+A\,b^3\,d\,e\right )}{2\,e^3}+\frac {b^2\,x^3\,\left (A\,b\,e+3\,B\,a\,e-4\,B\,b\,d\right )}{e^2}}{d^4+4\,d^3\,e\,x+6\,d^2\,e^2\,x^2+4\,d\,e^3\,x^3+e^4\,x^4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((A + B*x)*(a + b*x)^3)/(d + e*x)^5,x)

[Out]

(B*b^3*log(d + e*x))/e^5 - ((3*A*a^3*e^4 - 25*B*b^3*d^4 + 3*A*b^3*d^3*e + B*a^3*d*e^3 + 3*A*a*b^2*d^2*e^2 + 3*
B*a^2*b*d^2*e^2 + 3*A*a^2*b*d*e^3 + 9*B*a*b^2*d^3*e)/(12*e^5) + (x*(B*a^3*e^3 - 22*B*b^3*d^3 + 3*A*a^2*b*e^3 +
3*A*b^3*d^2*e + 3*A*a*b^2*d*e^2 + 9*B*a*b^2*d^2*e + 3*B*a^2*b*d*e^2))/(3*e^4) + (3*x^2*(A*b^3*d*e - 6*B*b^3*d
^2 + A*a*b^2*e^2 + B*a^2*b*e^2 + 3*B*a*b^2*d*e))/(2*e^3) + (b^2*x^3*(A*b*e + 3*B*a*e - 4*B*b*d))/e^2)/(d^4 + e
^4*x^4 + 4*d*e^3*x^3 + 6*d^2*e^2*x^2 + 4*d^3*e*x)

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sympy [B]  time = 32.19, size = 359, normalized size = 2.78 \begin {gather*} \frac {B b^{3} \log {\left (d + e x \right )}}{e^{5}} + \frac {- 3 A a^{3} e^{4} - 3 A a^{2} b d e^{3} - 3 A a b^{2} d^{2} e^{2} - 3 A b^{3} d^{3} e - B a^{3} d e^{3} - 3 B a^{2} b d^{2} e^{2} - 9 B a b^{2} d^{3} e + 25 B b^{3} d^{4} + x^{3} \left (- 12 A b^{3} e^{4} - 36 B a b^{2} e^{4} + 48 B b^{3} d e^{3}\right ) + x^{2} \left (- 18 A a b^{2} e^{4} - 18 A b^{3} d e^{3} - 18 B a^{2} b e^{4} - 54 B a b^{2} d e^{3} + 108 B b^{3} d^{2} e^{2}\right ) + x \left (- 12 A a^{2} b e^{4} - 12 A a b^{2} d e^{3} - 12 A b^{3} d^{2} e^{2} - 4 B a^{3} e^{4} - 12 B a^{2} b d e^{3} - 36 B a b^{2} d^{2} e^{2} + 88 B b^{3} d^{3} e\right )}{12 d^{4} e^{5} + 48 d^{3} e^{6} x + 72 d^{2} e^{7} x^{2} + 48 d e^{8} x^{3} + 12 e^{9} x^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**3*(B*x+A)/(e*x+d)**5,x)

[Out]

B*b**3*log(d + e*x)/e**5 + (-3*A*a**3*e**4 - 3*A*a**2*b*d*e**3 - 3*A*a*b**2*d**2*e**2 - 3*A*b**3*d**3*e - B*a*
*3*d*e**3 - 3*B*a**2*b*d**2*e**2 - 9*B*a*b**2*d**3*e + 25*B*b**3*d**4 + x**3*(-12*A*b**3*e**4 - 36*B*a*b**2*e*
*4 + 48*B*b**3*d*e**3) + x**2*(-18*A*a*b**2*e**4 - 18*A*b**3*d*e**3 - 18*B*a**2*b*e**4 - 54*B*a*b**2*d*e**3 +
108*B*b**3*d**2*e**2) + x*(-12*A*a**2*b*e**4 - 12*A*a*b**2*d*e**3 - 12*A*b**3*d**2*e**2 - 4*B*a**3*e**4 - 12*B
*a**2*b*d*e**3 - 36*B*a*b**2*d**2*e**2 + 88*B*b**3*d**3*e))/(12*d**4*e**5 + 48*d**3*e**6*x + 72*d**2*e**7*x**2
+ 48*d*e**8*x**3 + 12*e**9*x**4)

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